X^2+14x=2x-32

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Solution for X^2+14x=2x-32 equation:



X^2+14X=2X-32
We move all terms to the left:
X^2+14X-(2X-32)=0
We get rid of parentheses
X^2+14X-2X+32=0
We add all the numbers together, and all the variables
X^2+12X+32=0
a = 1; b = 12; c = +32;
Δ = b2-4ac
Δ = 122-4·1·32
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16}=4$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-4}{2*1}=\frac{-16}{2} =-8 $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+4}{2*1}=\frac{-8}{2} =-4 $

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